SOLUTION: Mr. Javier designed an arch made of
bent iron for the top of a school’s main
entrance. The 12 segments between
the two concentric semicircles are
each 0.8 meter long. Suppose
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-> SOLUTION: Mr. Javier designed an arch made of
bent iron for the top of a school’s main
entrance. The 12 segments between
the two concentric semicircles are
each 0.8 meter long. Suppose
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Question 997080: Mr. Javier designed an arch made of
bent iron for the top of a school’s main
entrance. The 12 segments between
the two concentric semicircles are
each 0.8 meter long. Suppose the
diameter of the inner semicircle is 4
meters. What is the total length of the
bent iron used to make this arch?
please help me to solve this problem, please help me. thank you Answer by KMST(5328) (Show Source):
It may look like this: or maybe the 12 straight segments are placed between the two semicircles
in a different arrangement.
There are each, for a total of .
There are also half-circle arcs.
The inside arc has a radius of .
The outside arc has a radius of .
Since the circumference of a circle of radius can be calculated as ,
the length of a semicircle of radius can be calculated as .
So, the length needed for the inside semicircle is ,
and the length needed for the outside semicircle is .
The total length of the bent iron used to make the arch is about .
