SOLUTION: Find the equation of the line x+3y+1=0 and passing through the point where 3x-2y+6=0 cuts the x-axis?

Algebra ->  Points-lines-and-rays -> SOLUTION: Find the equation of the line x+3y+1=0 and passing through the point where 3x-2y+6=0 cuts the x-axis?      Log On


   

Question 996133: Find the equation of the line x+3y+1=0 and passing through the point where 3x-2y+6=0 cuts the x-axis?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
3x-2%2A0%2B6=0
3x=-6
x=-2
-
Point (-2,0).

x%2B3y%2B1=0
change to
x%2B3y%2Bc=0
c=-x-3y
c=-%28-2%29-3%280%29
c=2
-
Resulting equation found, x%2B3y%2B2=0.
This may not be what you really want. The problem description is lacking. This found line is PARALLEL to the first equation mentioned in your description and passes through the intercept of your second equation of your description.