SOLUTION: The diameter of a circle has endpoints J(12,25) and K(-10,13). Find the circumstance and area the circle. Use the pie key on your calculator and round to the nearest tenth.

Algebra ->  Circles -> SOLUTION: The diameter of a circle has endpoints J(12,25) and K(-10,13). Find the circumstance and area the circle. Use the pie key on your calculator and round to the nearest tenth.      Log On


   

Question 990600: The diameter of a circle has endpoints J(12,25) and K(-10,13). Find the circumstance and area the circle. Use the pie key on your calculator and round to the nearest tenth.
Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
Hi dear,
Use sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29
Where y1=25,y2=13,x1=12,x2=-10
put the above in the formula and get diameter of the circle to be 25.01
Now radius r=25.01/2
=12.51
circumference=2*pi*12.51
=78.61
area=pi*12.51²
=941.72