SOLUTION: Angle A=3x-10 and Angle B=x+40. angle A and B are corresponding angles formed by two parallel lines intersected by transversal. find x,and the measures of angles A and B

Algebra ->  Points-lines-and-rays -> SOLUTION: Angle A=3x-10 and Angle B=x+40. angle A and B are corresponding angles formed by two parallel lines intersected by transversal. find x,and the measures of angles A and B      Log On


   



Question 985823: Angle A=3x-10 and Angle B=x+40. angle A and B are corresponding angles formed by two parallel lines intersected by transversal. find x,and the measures of angles A and B
Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
Hi dear,
Recall that corresponding angles are equal
Therefore,
A=B
i.e,3x-10=x+40
3x-x=40+10
2x=50
x=25
measure if A=3(25)-10
=75-10
=65
measure of B=25+40
=65