SOLUTION: A circle has equation
x^2+ax+y^2+by+c = 0
What is the exact value of the x-coordinate of the centre of the circle when a = 134, b = -84 and c = 163?
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-> SOLUTION: A circle has equation
x^2+ax+y^2+by+c = 0
What is the exact value of the x-coordinate of the centre of the circle when a = 134, b = -84 and c = 163?
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Question 982705: A circle has equation
x^2+ax+y^2+by+c = 0
What is the exact value of the x-coordinate of the centre of the circle when a = 134, b = -84 and c = 163? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there
x^2+ax+y^2+by+c = 0
Substituting the values
x^2 + y^2 + 134x - 84y + 163
For x coord:
Halve 134 and make it negative
= -67
For y coord
Halve -84 and make it negative
= 42
Coordinates of centre = (-67,42)
Hope this helps:-)
