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Question 980428: Can someone please solve these 3 coordinate geometry in the x, y plane questions for me? It would really help. E out. Preferably if you show your working out too so I can see how it's done.
2) the line PQ is a diameter of the circle center (-4,-2). The line l(small L) passes through P and is perpendicular to PQ. Given that Q is (10,4), find the equation of l.
Thank you!!
Answer by josgarithmetic(39618)   (Show Source):
You can put this solution on YOUR website! P, and Q, and the center, are collinear. You can find the slope of this line, and then calculate the negative reciprocal of this slope.
If point C is the center of this circle, m is slope of the two points CQ, then you want to know  for the perpendicular line you want to find.
Use the point-slope form of linear equation and form the equation accordingly, and then transform into whatever form you want. Here, you already know as given the desired line must go through center (-4,-2):
... Do what you need.
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