Question 975591: What is the equation,in general form,of the circle whose center is (3,-2)and which contains the point (-1,-2)?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! What is the equation,in general form,of the circle whose center is (3,-2)and which contains the point (-1,-2)?
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Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h.k)=coordinates of center, r=radius
For given problem:
(x-h)^2+(y-k)^2=r^2
solve for r^2:
plug in coordinates of center
(x-3)^2+(y+2)^2=r^2
plug in coordinates(-1, -2) of given point on the circle
(-1-3)^2+(-2+2)^2=r^2
16=r^2
r=4
equation: (x-3)^2+(y+2)^2=4
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