SOLUTION: for the equation of a circle x^2+y^2-6y=27,complete the square to put it in the form (x-h)^2+(y-k)^2=r^2, then give the center and radius.
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-> SOLUTION: for the equation of a circle x^2+y^2-6y=27,complete the square to put it in the form (x-h)^2+(y-k)^2=r^2, then give the center and radius.
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Question 972179: for the equation of a circle x^2+y^2-6y=27,complete the square to put it in the form (x-h)^2+(y-k)^2=r^2, then give the center and radius. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! (x^2) + (y2-6y+ -----) =27
x^2 + (y^2+6y +9)=27+9
x^2 + (y+3)^2 =36
This is a circle with center (0.-3) and radius 6,
x-h ; h=0
y-k; k=-3
sqrt 36=6
