SOLUTION: Change the equation to standard form x^2+ y^2 - 2x + 14y + 1 = 0

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Question 968469: Change the equation to standard form
x^2+ y^2 - 2x + 14y + 1 = 0

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Change the equation to standard form
x^2+ y^2 - 2x + 14y + 1 = 0
x%5E2%2B+y%5E2+-+2x+%2B+14y+%2B+1%22%22=%22%22%220%22

Get the like letter terms together and subtract the constant term from
both sides:

x%5E2+-+2x+%2B+y%5E2+%2B+14y+%22%22=%22%22-1

Put parentheses around the x terms and the y terms,
skipping a space after each:

%22%22=%22%22-1

Complete the square in the first parentheses:
1. Multiply the coefficient of x, which is -2 by 1/2, getting -1
2. Square -1.  (-1)2, getting +1
3. Add it in the space in the first parentheses, and also add it
to the right side:

%28x%5E2+-+2x%2B1%29+%2B+%28y%5E2+%2B+14y%2Bmatrix%281%2C3%2C%22%22%2C%22%22%2C%22%22%29%29+%22%22=%22%22-1%2B1

Complete the square in the second parentheses:
1. Multiply the coefficient of x, which is 14 by 1/2, getting 7
2. Square 7.  (7)2, getting +49
3. Add it in the space in the second parentheses, and also add it 
to the right side:

%28x%5E2+-+2x%2B1%29+%2B+%28y%5E2+%2B+14y%2B49%29+%22%22=%22%22-1%2B1%2B49

Factor each parentheses and combine numbers on the right:

%28x-1%29%28x-1%29%2B%28y%2B7%29%28y%2B7%29=49

Write the factorizations as squares:

%28x-1%29%5E2%2B%28y%2B7%29%5E2=49

Edwin