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Question 967652: find the angle from the line x+2y-3=0 to the line 2x-3y+8=0.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! find the angle from the line x+2y-3=0 to the line 2x-3y+8=0.
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Find the slope of each line.
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x+2y-3=0 --> y = (-1/2)x + b --> m1 = -1/2
2x-3y+8=0 --> y = (2/3)x + b --> m2 = 2/3
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The slope is the tangent of the angle wrt the x-axis.
Angle 1 = atan(-1/2) = -26.565 degs
Angle 2 = atan(2/3) = 33.69 degs
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The small angle at the intersection is the difference.
= 60.255 degs
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The large angle = 180 - 60.255 = 119.745 degs
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