SOLUTION: 1. A rock is thrown upward from the edge of a cliff. The rock follows the equation below. S = 20 + 64t – 16t2 What is the greatest height above the ground that this rock will g

Algebra ->  Points-lines-and-rays -> SOLUTION: 1. A rock is thrown upward from the edge of a cliff. The rock follows the equation below. S = 20 + 64t – 16t2 What is the greatest height above the ground that this rock will g      Log On


   

Question 966488: 1. A rock is thrown upward from the edge of a cliff. The rock follows the equation below.
S = 20 + 64t – 16t2
What is the greatest height above the ground that this rock will go?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A rock is thrown upward from the edge of a cliff. The rock follows the equation below.
S = 20 + 64t – 16t2
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s(t) = -16t^2 + 64t + 20
Max ht is the vertex of the parabola
At t = -b/2a = -64/-32 = 2 seconds
s(2) = -64 + 128 + 20
= 84 feet