SOLUTION: hello, please help me solve this math question: the figure is made up of four identical squares of side length 14 inches. A quadrant is drawn inside each square. find the total ar

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Question 959765: hello, please help me solve this math question:
the figure is made up of four identical squares of side length 14 inches. A quadrant is drawn inside each square. find the total area of the unshaded parts of the figure. you can find the diagram in the link below, question 9. thanks!
Link: http://ibkmartin.weebly.com/uploads/1/0/3/4/10343187/chapter_8_study_guide.pdf

Found 2 solutions by macston, MathLover1:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Take the area of the large (28" x 28") square, subtract the area of the 14" radius circle
and add back the area of the inner square (1/2 the area of 4 - 14" x 14" squares):
Shaded Area=large square area-circle area+small square area
Shaded area=%2828in%29%5E2-%28pi%29%2814in%29%5E2%2B%284%29%281%2F2%29%2814in%29%5E2
Shaded area=784in%5E2-%2822%2F7%29196in%5E2%2B392in%5E2
Shaded area=784in%5E2-616in%5E2%2B392in%5E2=560in%5E2
ANSWER: The shaded area is 560 square inches.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

inside square: side a has an area of A%5Bs%5D=a%5E2
from one right-angle triangle with hypotenuse a, and legs each 14in we have
a%5E2=14%5E2%2B14%5E2
a%5E2=196%2B196
a%5E2=392
A%5Binside-square%5D=a%5E2=392
then the area should be deducted from the area of the circle with radius r=14
A%5Bcircle%5D=r%5E2%2Api
A%5Bcircle%5D=14%5E2%2A%2822%2F7%29
A%5Bcircle%5D=196%2A%2822%2F7%29
A%5Bcircle%5D=196%2A3.142857142857143
A%5Bcircle%5D=616
shaded area is the difference between area of the
A%5Bshaded%5D=A%5Bcircle%5D-A%5Binside-square%5D
A%5Bshaded%5D=616-392
A%5Bshaded%5D=224in%5E2................shaded area

unshaded area is the difference between area of the large square whose 2%2A14=28in side is and shaded area
the large square area A=%2828%29%5E2=>A=784in%5E2

unshaded area will be
A%5Bunshaded%5D=784-224
A%5Bunshaded%5D=560in%5E2