SOLUTION: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2)
the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0
please
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-> SOLUTION: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2)
the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0
please
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Question 949360: find equation of the circle that has radius of 5 and tangent to the line 3x+4y=24 at the point (2, 4 1/2)
the answer is 4x^2+4y^2+8-4y-95=0 or 4x^2+4y^2-40x-68y+289=0
please tell me how did it come up to those answers.
thank you Answer by josgarithmetic(39621) (Show Source):
You can put this solution on YOUR website! Mistake made in solution, so removed.
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