SOLUTION: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36. Find the slope of L. Decimal approximations will be marked incorrect

Algebra ->  Points-lines-and-rays -> SOLUTION: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36. Find the slope of L. Decimal approximations will be marked incorrect      Log On


   



Question 941934: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36.
Find the slope of L. Decimal approximations will be marked incorrect.

Answer: 3/2
This is what I'm having trouble with:
Write an equation for L in terms of the variables x and y. Decimal approximations will be marked incorrect.
I'm not sure what it wants? I tried using the point-slope form as y=(3/2)(x-6)+9, but it said that was incorrect.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the line passing through the point (6, 9) and the center (h,k) of the circle %28x+-4%29%5E2+%2B+%28y+-6%29%5E2+=+36
since %28x+-4%29%5E2+%2B+%28y+-6%29%5E2+=+36 we know that h=4 and k=6 (recall the circle formula %28x+-h%29%5E2+%2B+%28y+-k%29%5E2+=+r%5E2 )
so, we have two points the point (6, 9) and the point (4, 6)
now find equation of a line passing through these two points:
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (6, 9) and (x2, y2) = (4, 6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-9%29%2F%284-6%29+=+1.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 1.5%2A6+%2Bb+=+0. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=9-1.5%2A6+=+0.

y=(1.5)x + (0)

Your graph:




since equation is y=1.5%2Ax which is y=%283%2F2%29x; so, the slope is 3%2F2