Question 941799: Find the equaton of the circle with radius 6 and whose center lies at the intersection of the lines 3x+y=1 and -2x-3y=4
Answer by srinivas.g(540)   (Show Source):
You can put this solution on YOUR website! equation of circle in standard form: 
where center =(h,k) , radius =r
center lies at the intersection of the lines 3x+y=1 and -2x-3y=4
3x+y =1......eq(1)
-2x-3y =4........eq(2)
| Solved by pluggable solver: SOLVE linear system by SUBSTITUTION |
Solve:
 We'll use substitution. After moving 1*y to the right, we get:
 , or  . Substitute that
into another equation:
 and simplify: So, we know that y=-2. Since , x=1.
Answer:  .
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(x,y)=(1,-2)
center(h,l)= (1,-2)
equation circle becomes
Result :
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