SOLUTION: If the dimensions of a geometric are doubled , its perimeter and its area?

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Question 917362: If the dimensions of a geometric are doubled , its perimeter and its area?
Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let's take a look at this problem.
Rectangle Perimeter+=+2%28l+%2B+w%29
if doubles Perimeter+=+2%2A2%282l+%2B+2w%29+
+Perimeter+=+4%28l+%2B+w%29
=>2+Perimeter+=+2%28l+%2B+w%29
thus, we can say that the perimeter of a rectangle is doubled+when its dimensions are doubled
Rectangle Area+=+lw
Area+=+%282l%29%282w%29
Area+=+4lw+
=>4%28Rectangle+Area%29+=+4lw
Thus, we can say that the area of a rectangle is quadruplicated+when its dimensions are doubled.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If the dimensions of a geometric are doubled , its perimeter and its area?
Original Dimentions:: L and W
New Dimentions:: 2L and 2W
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Original Perimether = 2(L+W)
New Perimeter = 2(2L + 2W) = 2(2(L+W))
Perimeter is increased by a factor of 2.
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Original Area = L*W
New Area = (2L)(2W) = 4(LW)
Area is increased by a factor of 4
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Cheers,
Stan H.
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