SOLUTION: Find the equation of the line through the given point and perpendicular to the given line.
(0,0); -2x+4y=12
Algebra ->
Points-lines-and-rays
-> SOLUTION: Find the equation of the line through the given point and perpendicular to the given line.
(0,0); -2x+4y=12
Log On
Question 911879: Find the equation of the line through the given point and perpendicular to the given line.
(0,0); -2x+4y=12 Found 2 solutions by stanbon, ewatrrr:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the equation of the line through the given point and perpendicular to the given line.
(0,0);-2x+4y=12
---------------------
Given line -2x+4y = 12, find the slope::
4y = 2x + 12
y = (1/2)x + 3
slope = 1/2
----
Slope you want must be -2.
----
Form:: y = mx + b
Solve for "b" by substitution::
0 = (-2)*0 + b
b = 0
--------------
Ans: y = -2x
=================
Cheers,
Stan H.
-----------------
You can put this solution on YOUR website! perpendicular to: -2x+4y=12 0r y = (1/2)x + 3, m = 1/2
New Line
m = -2 (Negative Reciprocal)
***Using point-slope form, P(0,0)
y = -2x
(