SOLUTION: Diagram of circle with outer edge shaded. The outer circle has diameter 8 inches. The area of the shaded ring is equal to the are of the inner, non-shaded circle. What is the radi

Algebra ->  Circles -> SOLUTION: Diagram of circle with outer edge shaded. The outer circle has diameter 8 inches. The area of the shaded ring is equal to the are of the inner, non-shaded circle. What is the radi      Log On


   



Question 909337: Diagram of circle with outer edge shaded. The outer circle has diameter 8 inches. The area of the shaded ring is equal to the are of the inner, non-shaded circle. What is the radius of the inner circle? Express your answer as a decimal to the nearest tenth.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
R, radius of the outer circle
r, radius of the inner (smaller) circle
R=8%2F2=4 inches
r is unknown.

Area of outer circle, pi%2AR%5E2;
Area of smaller inner circle, pi%2Ar%5E2;
Difference in areas is the area of your shaded ring surrounding the inner circle, pi%2AR%5E2-pi%2Ar%5E2.

According to the description, pi%28R%5E2-r%5E2%29=pi%2Ar%5E2.
You want to solve for r.

STEPS
Divide both members by pi.
R%5E2-r%5E2=r%5E2
R%5E2=2r%5E2
r%5E2=%281%2F2%29R%5E2
r=R%2Fsqrt%282%29, and you might want to rationalize the denominator.
r=%28R%2Fsqrt%282%29%29%28sqrt%282%29%2Fsqrt%282%29%29
highlight%28r=R%2Asqrt%282%29%2F2%29----the symbolic answer.

Substitute for R and evaluate r.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Diagram of circle with outer edge shaded. The outer circle has diameter 8 inches. The area of the shaded ring is equal to the are of the inner, non-shaded circle. What is the radius of the inner circle? Express your answer as a decimal to the nearest tenth.

Let radius of smaller, non-shaded, inner circle, be r
Then area of smaller, non-shaded circle is: pi%2Ar%5E2
Now, since the area of the smaller, non-shaded circle and the shaded area are equal, then
the area of the smaller, non-shaded circle and the shaded region = 2%28pi%2Ar%5E2%29, or 2pi%2Ar%5E2
Area of larger circle is: pi%2A4%5E2, or 16pi
Therefore, we get: 2pi%2Ar%5E2+=+16pi
2pi%2A%28r%5E2%29+=+2pi%2A%288%29 ------ Factoring out GCF, 2pi
r%5E2+=+8
r, or radius of smaller, non-shaded, inner circle = sqrt%288%29, or 2sqrt%282%29, or 2.828427125highlight_green%282.8%29 inches