SOLUTION: Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. First, you will need to find th
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-> SOLUTION: Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. First, you will need to find th
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Question 901283: Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. First, you will need to find the area of the smaller segment.) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius.
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Find 1/2 the angle at the center of the right triangle with hypotenuse = 8 and side = 4 --> 30 degrees.
Area of the sector = Area of the circle/6 = CA/6 = pi*r^2/6 = 32pi/3
Area of the 2 30-60-90 triangles = 2*bh/2 = 4*8*cos(30) = 16sqrt(3)
Subtract the area of the 2 right triangles for CA/6
--> 32pi/3 - 16sqrt(3) [Area of small segment]
Large segment area = 64pi - small area
= 160pi/3 + 16sqrt(3) sq units
