SOLUTION: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0). a x2 + y2 = 25 b (x + 6)2 + y2 = 36 c (x - 6)2 + y2 = 25 d (x -

Algebra ->  Circles -> SOLUTION: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0). a x2 + y2 = 25 b (x + 6)2 + y2 = 36 c (x - 6)2 + y2 = 25 d (x -      Log On


   

Question 876359: Write the standard equation of a circle with center (6, 0) that passes through the point (0, 0).
a
x2 + y2 = 25
b
(x + 6)2 + y2 = 36
c
(x - 6)2 + y2 = 25
d
(x - 6)2 + y2 = 36
e
x2 + y2 = 36
f
(x + 6)2 + y2 = 25
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
%28x-6%29%5E2+%2B+%28y-0%29%5E2+=+6%5E2 radius must be 6 IF circle passes thru (0,0)