SOLUTION: What is the correct standard equation of a circle with center (-4, 0) and radius 9? a (x + 4)2 + y2 = 81 b (x - 4)2 + y2 = 9 c (x - 4)2 + y2 = 81 d (x + 4)2 + y

Algebra ->  Circles -> SOLUTION: What is the correct standard equation of a circle with center (-4, 0) and radius 9? a (x + 4)2 + y2 = 81 b (x - 4)2 + y2 = 9 c (x - 4)2 + y2 = 81 d (x + 4)2 + y      Log On


   

Question 876335: What is the correct standard equation of a circle with center (-4, 0) and radius 9?
a
(x + 4)2 + y2 = 81
b
(x - 4)2 + y2 = 9
c
(x - 4)2 + y2 = 81
d
(x + 4)2 + y2 = 9
e
(x + 4)2 + y2 = 3
f
(x - 4)2 + y2 = 3
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
circle with center (-4, 0) and radius 9
a. (x + 4)^2 + y^2 = 81
Need to Know
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius