SOLUTION: Find an equation of the circle with center (13−8) and radius 1 in the form of (x−A)2+(y−B)2=C where ABC are constant.

Algebra ->  Circles -> SOLUTION: Find an equation of the circle with center (13−8) and radius 1 in the form of (x−A)2+(y−B)2=C where ABC are constant.       Log On


   

Question 874647: Find an equation of the circle with center (13−8) and radius 1 in the form of (x−A)2+(y−B)2=C where ABC are constant.
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
[I'm assuming that the center is (13, -8)]

The standard form for the equation of a circle is:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2
with (h, k) being the center of the circle and r being the radius.

Substituting in the given center and radius we get:
%28x-%2813%29%29%5E2%2B%28y-%28-8%29%29%5E2=%281%29%5E2
Simplifying the right side we get:
%28x-13%29%5E2%2B%28y-%28-8%29%29%5E2=1

P.S. Please post your questions in a relevant category. This problem has nothing to do with the category you used, rational expressions.