SOLUTION: Hi can someone please help me out on this? The diameter of a clock’s face is 6 inches. Find the length of the minor arc formed by the hands of the clock at 4:00. Round to the n

Algebra ->  Circles -> SOLUTION: Hi can someone please help me out on this? The diameter of a clock’s face is 6 inches. Find the length of the minor arc formed by the hands of the clock at 4:00. Round to the n      Log On


   

Question 871344: Hi can someone please help me out on this?
The diameter of a clock’s face is 6 inches. Find the length of the minor arc formed by the hands of the clock at 4:00. Round to the nearest hundredth.
Thanks a lot!
Found 2 solutions by mananth, ankor@dixie-net.com:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
diameter = 6 "
r=3"
2pir is the circumference
2*3*pi
6pi
Central angle at 4 .00 is 60 degrees
length of arc = %28%28theta%29%2F360%29%2A2pir
%281%2F6%29%2A6pi
=pi
3.142 inches

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The diameter of a clock’s face is 6 inches.
Find the length of the minor arc formed by the hands of the clock at 4:00.
Round to the nearest hundredth.
:
Find what portion of 360 degrees is 4 o'clock: 4/12 = 1/3
Find the circumference of the clock
C = pi%2A6 = 18.85 inchec
1%2F3 * 18.85 = 6.28 inches is the arc formed between the hands at 4 o'clock