SOLUTION: What is the center and radius of x^2 + y^2 - 14y + 48 = 0

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Question 870613: What is the center and radius of x^2 + y^2 - 14y + 48 = 0
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-14y=-48
x%5E2%2B%28y%5E2-14y%2B7%5E2%29=-48%2B7%5E2
highlight%28x%5E2%2B%28y-7%29%5E2=1%29

Center is (0,7) and radius is 1.