SOLUTION: End points of the radius are (-6,-2) and (4,2) , center is in the 3rd quadrant .

Algebra ->  Circles -> SOLUTION: End points of the radius are (-6,-2) and (4,2) , center is in the 3rd quadrant .      Log On


   

Question 854175: End points of the radius are (-6,-2) and (4,2) , center is in the 3rd quadrant .
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Clever way to say that the center is (-6,-2). The radius is r=sqrt%28%28-6-4%29%5E2%2B%28-2-2%29%5E2%29.
r=sqrt%28100%2B16%29
r=sqrt%28116%29, 116=2*58=2*2*29

Equation of the circle is highlight%28%28x%2B6%29%5E2%2B%28y%2B2%29%5E2=116%29