SOLUTION: a circle has its center on the line 3x-2y-22=0 and tangent to the y-axis at (0,1). Find its equation

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Question 850381: a circle has its center on the line 3x-2y-22=0 and tangent to the y-axis at (0,1). Find its equation
Answer by Alan3354(69443) About Me  (Show Source):
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a circle has its center on the line 3x-2y-22=0 and tangent to the y-axis at (0,1). Find its equation
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Tangent at (0,1) --> its center is also on the line y = 1
Find the intersection of the 2 lines, that's the center
3x-2y-22=0
y = 1
3x = 24
x = 8
Center at (8,1)
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r is the distance from the y-axis = 8
%28x-8%29%5E2+%2B+%28y-1%29%5E2+=+8%5E2