SOLUTION: Write an equation of the line containing the specified point and perpendicular to the indicated line:
(-5,6), 4x - y = 3
I have got this far and don't know where else to go w
Algebra ->
Points-lines-and-rays
-> SOLUTION: Write an equation of the line containing the specified point and perpendicular to the indicated line:
(-5,6), 4x - y = 3
I have got this far and don't know where else to go w
Log On
Question 843174: Write an equation of the line containing the specified point and perpendicular to the indicated line:
(-5,6), 4x - y = 3
I have got this far and don't know where else to go with it:
4x - y = 3
y = -4 + 3
Slope of line is:
m = 4
y = 1/4x + b
4 = (1/4) (-5) +b =
However, I do not feel that this is correct, so I am asking for help on solving this problem. I have spent the last two hours trying to figure it out and I need help.
Thank You,
Sharon Found 2 solutions by richwmiller, LinnW:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! y=4x-3
slope is 4
perpendicular slope is -1/4
6=-1/4(-5)+b
6=-5/4+b
6+5/4=b
29/4=b
7 1/4=b
any of three following equations will be the line perpendicular
y=-1/4x+7 1/4
4y=-x+29
x+4y=29
You can put this solution on YOUR website! 4x - y = 3 become
y = 4x -3
The slope of the perpendicular is the negative inverse of 4
so we want 4*inverse = -1
inverse = -1/4
Using y = mx + b as a template with m = -1/4 , x= -5 and y = 6
6 = (-1/4)(-5) + b
6 = 5/4 + b
subtract 5/4 from each side
4 3/4 = b
Our equations is y = (-1/4)x + 4 3/4
Let me know if this helps.
