SOLUTION: Find the General Equation of the circle 5) With radius 3 touching both axes

Algebra ->  Circles -> SOLUTION: Find the General Equation of the circle 5) With radius 3 touching both axes      Log On


   



Question 832265: Find the General Equation of the circle
5) With radius 3 touching both axes

Found 2 solutions by Fombitz, nerdybill:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Touching both axes gives you 4 possible circle choices.
The center of the circle could be at (3,3),(3,-3),(-3,3) or (-3,-3).
The general equation of a circle is,
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
where (h,k) is the center and R is the radius.
So, one choice would be,
%28x-3%29%5E2%2B%28y-3%29%5E2=9 with (3,3) as the center.
You can complete the other 3 choices similarly.

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Find the General Equation of the circle
5) With radius 3 touching both axes
If we want the circle in the upper right of the graph the center is at:
(3,3)
General equation of a circle is
(x-h)^2 + (y-k)^ = r^2
plugging in what we know:
(x-3)^2 + (y-3)^ = 3^2
or
(x-3)^2 + (y-3)^ = 9