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Question 823152: What is the equation of a line that is perpendicular to 6x+3y=2 and passes through the point (-2,4)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What is the equation of a line that is perpendicular to 6x+3y=2 and passes through the point (-2,4)
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Determine the slope of the given line:
3y = -6x+2
y = -2x + (2/3)
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slope = -2
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Any line perpendicular to the given line must have slope = 1/2
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Form: y = mx + b
Solve for "b":
4 = (1/2)(-2) + b
4 = -1 + b
b = 5
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Equation:
y = (1/2)x + 5
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Cheers,
Stan H.
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