SOLUTION: I'm given the points A(2,-2) & B(4,4), I have found |AB| to be 2sqrt10 , I found the midpoint to be (3,1), the slope to be 3 & the equation of the line to be 3x-y-8=0. The next par

Algebra ->  Points-lines-and-rays -> SOLUTION: I'm given the points A(2,-2) & B(4,4), I have found |AB| to be 2sqrt10 , I found the midpoint to be (3,1), the slope to be 3 & the equation of the line to be 3x-y-8=0. The next par      Log On


   



Question 817866: I'm given the points A(2,-2) & B(4,4), I have found |AB| to be 2sqrt10 , I found the midpoint to be (3,1), the slope to be 3 & the equation of the line to be 3x-y-8=0. The next part of the question says the point (-2,r) is on the line AB & I've to find the value of r? I do not know how to! Help please
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of the line that has AB as a segment you have correctly determined to be
y = 3x -8
we are given point (-2, r) and asked to determine r
substitute -2 for x in the equation of your line
y = 3*(-2) -8
y = -14, therefore
r = -14