SOLUTION: Find the equation of a circle whose diameter has endpoints (4, -1) and (-6, 7).

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Question 813344: Find the equation of a circle whose diameter has endpoints (4, -1) and (-6, 7).
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

circle whose diameter has endpoints (4, -1) and (-6, 7).

D = sqrt+%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29%29

D = sqrt+%28%2810%5E2%2B+%28-8%29%5E2%29%29+=+sqrt%28164%29+=+2sqrt%2841%29

r = sqrt%2841%29

Midpoint Pt(x,y):  ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)



Midpoint Pt(x,y):  (-2/2 , 6/2)  0r  (-1,3)

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius

%28x%2B1%29%5E2+%2B+%28y-3%29%5E2+=+41