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Question 811808: A steel bar 6.50 inches in diameter is being turned in a lathe. The surface speed of the bar is 55.0 feet per minute. How many revolutions will the bar make in 10.0 seconds?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! C = 2 pi R
C = 2 * 3.1415 * 3.25 in * (1/12 ft/in) = 1.7016 ft
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revs per minute (rpm):
55 ft/min * (1/1.7016) rev/ft = 32.321 rpm
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revs per second (rps):
32.321 rev/min * (1/60) min/sec = 0.539 rps
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revs per 10 seconds:
0.539 rev/sec * 10 sec = 5.39 revs
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