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Question 80580: L has y-intercept (0, -3) and is parallel to the line with the equation y=2/3x + 1,
L has y-intercept (0,2) and is perpendicular to the line with equation 2x - 3y=6.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! L has y-intercept (0, -3) and is parallel to the line with the equation y=2/3x + 1,
The slope is 2/3 and the y intercept is -3.
So the equation is y=(2/3)x-3
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L has y-intercept (0,2) and is perpendicular to the line with equation
2x - 3y=6.
The slope of the given line is (2/3) so the slope of the perdicular line
must be -3/2
So the equation of the perpendicular line is y=(-3/2)x+2
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Cheers,
Stan H.
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