SOLUTION: What is the general form of the equation of the given circle with center A? A(-3,12) r=5

Algebra ->  Circles -> SOLUTION: What is the general form of the equation of the given circle with center A? A(-3,12) r=5      Log On


   

Question 801792: What is the general form of the equation of the given circle with center A?
A(-3,12) r=5
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
(x - a)^2 + (y - b)^2 = r^2
(x + 3)^2 + (y - 12)^2 = 25
= x^2 + y^2 + 6x - 24y + 128 = 0
Hope this helps.
:-)