Question 800482: Please help me!! I do not understand how to do this question!
The equation of he circle is x^2 + y^2 = 6*x + 8*y -24 = 0. Find the equation of the diameter of the circle which passes through the point (-1,1).
Please help me!! I do not understand this question, how do I do it?!
Thank you!
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! I am not too sure if you have typed correctly
x^2 + y^2 + 6*x + 8*y -24 = 0
x^2-6x +y^2+8y -24=0
x^2-6x+9 +y^2+8y+16=24+9+16
(x+3)^2+(y+4)^2=49
center =(3,-4)
The other point is (-1,1)
Find the equation of line passing through (-1,1) and (3,-4)
(y-1)/(1+4) =(x-(-1))/(-1-3)
(y-1)/5 =(x+1)/-4
-4(y-1)=5(x+1)
-4y+4=5x+5
5x+4y+1=0
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