SOLUTION: Find the standard form for the equation of a circle with equation (x-h)^2+ (y-k)^2=r2 with a diameter that has endpoints (-5,8) and (9,4) i got 53 for the radio and found

Algebra ->  Circles -> SOLUTION: Find the standard form for the equation of a circle with equation (x-h)^2+ (y-k)^2=r2 with a diameter that has endpoints (-5,8) and (9,4) i got 53 for the radio and found       Log On


   



Question 785341: Find the standard form for the equation of a circle with equation (x-h)^2+ (y-k)^2=r2

with a diameter that has endpoints (-5,8) and (9,4)
i got 53 for the radio and found the midpoint coordinates (2,6) however my answer is still wrong, please help me!

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of a circle with equation %28x-h%29%5E2%2B+%28y-k%29%5E2=r%5E2

with a diameter that has endpoints (-5,8) and (9,4)
first find diameter d which is equal to distance between two given points:
Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-5, 8), we can say (x1, y1) = (-5, 8)
So x%5B1%5D+=+-5, y%5B1%5D+=+8


Since the second point is (9, 4), we can also say (x2, y2) = (9, 4)
So x%5B2%5D+=+9, y%5B2%5D+=+4


Put this all together to get: x%5B1%5D+=+-5, y%5B1%5D+=+8, x%5B2%5D+=+9, and y%5B2%5D+=+4

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Now use the distance formula to find the distance between the two points (-5, 8) and (9, 4)



d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29


d+=+sqrt%28%28-5+-+9%29%5E2+%2B+%288+-+4%29%5E2%29 Plug in x%5B1%5D+=+-5, y%5B1%5D+=+8, x%5B2%5D+=+9, and y%5B2%5D+=+4


d+=+sqrt%28%28-14%29%5E2+%2B+%284%29%5E2%29


d+=+sqrt%28196+%2B+16%29


d+=+sqrt%28212%29


d+=+sqrt%284%2A53%29


d+=+sqrt%284%29%2Asqrt%2853%29


d+=+2%2Asqrt%2853%29


d+=+14.560219778561

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Answer:


The distance between the two points (-5, 8) and (9, 4) is exactly 2%2Asqrt%2853%29 units


The approximate distance between the two points is about 14.560219778561 units



So again,


Exact Distance: 2%2Asqrt%2853%29 units


Approximate Distance: 14.560219778561 units




since d=14.56
now we know that radius is d%2F2=r=+7.28
now, find coordinates of the center which will be midpoint of diameter:
Solved by pluggable solver: Midpoint


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-5, 8), we can say (x1, y1) = (-5, 8)
So x%5B1%5D+=+-5, y%5B1%5D+=+8


Since the second point is (9, 4), we can also say (x2, y2) = (9, 4)
So x%5B2%5D+=+9, y%5B2%5D+=+4


Put this all together to get: x%5B1%5D+=+-5, y%5B1%5D+=+8, x%5B2%5D+=+9, and y%5B2%5D+=+4

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Finding the x coordinate of the midpoint: Add up the corresponding x coordinates x1 and x2 and divide that sum by 2


X Coordinate of Midpoint = %28x%5B1%5D%2Bx%5B2%5D%29%2F2


X Coordinate of Midpoint = %28-5%2B9%29%2F2


X Coordinate of Midpoint = 4%2F2


X Coordinate of Midpoint = 2



So the x coordinate of the midpoint is 2


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Finding the y coordinate of the midpoint: Add up the corresponding y coordinates y1 and y2 and divide that sum by 2


Y Coordinate of Midpoint = %28y%5B1%5D%2By%5B2%5D%29%2F2


Y Coordinate of Midpoint = %288%2B4%29%2F2


Y Coordinate of Midpoint = 12%2F2


Y Coordinate of Midpoint = 6


So the y coordinate of the midpoint is 6



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Summary:


The midpoint of the segment joining the two points (-5, 8) and (9, 4) is (2, 6).


So the answer is (2, 6)




as you can see, the midpoint of the segment joining the two points (-5,8) and (9,4) is (2, 6) which means h=2 and k=6
so, equation of a circle will be:
%28x-2%29%5E2%2B+%28y-6%29%5E2=%287.28%29%5E2
%28x-2%29%5E2%2B+%28y-6%29%5E2=53