SOLUTION: The centers of two circles are 51 centimeters apart. The smaller circle has a radius of 7 centimeters and the larger circle has a radius of 9 centimeters. Find the length of the co
Algebra ->
Circles
-> SOLUTION: The centers of two circles are 51 centimeters apart. The smaller circle has a radius of 7 centimeters and the larger circle has a radius of 9 centimeters. Find the length of the co
Log On
Question 782939: The centers of two circles are 51 centimeters apart. The smaller circle has a radius of 7 centimeters and the larger circle has a radius of 9 centimeters. Find the length of the common internal tangent (from the point of tangency on one circle to the point of tangency on the other circle). Give both an exact answer, and an approximate answer rounded to the nearest ten thousandth. Answer by Edwin McCravy(20059) (Show Source):
We let AC = x and therefore CD = 51-x.
Triangles ABC and DEC are similar and so their sides are
proportional.
Cross-multiply:
9x = 7(51-x)
9x = 357 - 7x
16x = 357
x = = 7² + BC²
= 49 + BC²
Clear of fractions by multiplying through by 256
127449 = 12544 + 256BC²
114905 = 256BC²
= BC²
= BC²
= BC
= BC
I could use ratio and proportion to get EC, but since
BC came out so complicated, I'll use the Pythagorean theorem
again.
DC = 51-x = 51 - = - =
DC² = DE² + EC²
= 9² + EC²
= 81 + EC²
Clear of fractions by multiplying through by 256
210681 = 20736 + 256EC²
189945 = 256EC²
= EC²
= EC²
= EC
= EC
So we find the internal tangent BE,
BE = BC + EC = + = = = √2345
Exact answer = √2345
approximate answer rounded to the nearest ten thousandth = 48.4252
Edwin