SOLUTION: How would you find the slope and y-intercept of these lines: y=3x-8 4x-2y=-7 x/4+y/3=1 Thank you p.s I did try but just don't understand :(

Algebra ->  Points-lines-and-rays -> SOLUTION: How would you find the slope and y-intercept of these lines: y=3x-8 4x-2y=-7 x/4+y/3=1 Thank you p.s I did try but just don't understand :(       Log On


   



Question 781616: How would you find the slope and y-intercept of these lines:
y=3x-8
4x-2y=-7
x/4+y/3=1
Thank you
p.s I did try but just don't understand :(

Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept

Get all equations in slope-intercept form and pick out the slope and y-intercept.
y = 3x - 8 {already in slope-intercept form}
slope = 3
y-intercept = -8

4x - 2y = -7
-2y = -4x - 7 {subtracted 4x from each side}
y = 2x + 7/2 {divided each side by -2}
slope = 2
y-intercept = 7/2

x/4 + y/3 = 1
12(x/4 + y/3 = 1) {multiplied entire equation by least common denominator, 12, to eliminate fractions}
12(x/4) + 12(y/3) = 12(1) {multiplied each term by 12}
3x + 4y = 12 {multiplied}
4y = -3x + 12 {subtracted 3x from each side}
y = (-3/4)x + 3 {divided each side by 4}
slope = -3/4
y-intercept = 3

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