SOLUTION: find the coordinates of the pointS equidistant from the axes and lying on the circle {{{ x^2 + y^2-6x-2y +6 =0 . i tried a lot but could not solve it...pls help.
Algebra ->
Circles
-> SOLUTION: find the coordinates of the pointS equidistant from the axes and lying on the circle {{{ x^2 + y^2-6x-2y +6 =0 . i tried a lot but could not solve it...pls help.
Log On
Question 781551: find the coordinates of the pointS equidistant from the axes and lying on the circle x^2 + y^2-6x-2y +6 =0 . i tried a lot but could not solve it...pls help.
You can put this solution on YOUR website! find the coordinates of the pointS equidistant from the axes and lying on the circle x^2 + y^2-6x-2y +6 = 0 .
------
Points equidistant from the axis lie on the line y = x or y = -x.
------
Complete the square on the equation::
x^2 -6x + 9 + y^2 -2y + 1 = -6+9+1
-----
(x-3)^2 + (y-1)^2 = 4
------
That equation has its center at (3,1) and has radius = 2; So
the circle is in the 1st Quadrant.
===============================
Let x = y, to get:
x^2 - 6x +9 + x^2 -2x + 6 = 0
2x^2 - 8x + 15 = 9
x = [8 +- sqrt(64-4*2*15)]/4
x = [8 +- sqrt(64-120)]/4
x = [8 +- sqrt(-56)]/4
----
These x-values are not Real Numbers.
The circle does not touch the line y = x
=================
Cheers,
Stan H.
=================
(