SOLUTION: hello, i need help on this question "find the equation of the circle with center (-6,2) and radius (2√(3)/3)" please and thank you.

Algebra ->  Circles -> SOLUTION: hello, i need help on this question "find the equation of the circle with center (-6,2) and radius (2√(3)/3)" please and thank you.      Log On


   

Question 775266: hello, i need help on this question "find the equation of the circle with center (-6,2) and radius (2√(3)/3)" please and thank you.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the formula of the circle:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where h and k are the x and y+coordinates of the center of the circle, and r is the radius
so,the equation of the circle with center (-6,2) and radius %282sqrt%283%29%2F3%29 is:
%28x%2B6%29%5E2%2B%28y-2%29%5E2=%282sqrt%283%29%2F3%29%5E2
%28x%2B6%29%5E2%2B%28y-2%29%5E2=%284%2A3%29%2F9
%28x%2B6%29%5E2%2B%28y-2%29%5E2=4%2F3