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Question 773824: Points A,C, and B are collinear. Point C is between A and B. AB=15. Find AC and BC if AC is twice as long as BC.
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! You'll need a drawing to see the parts clearly, but you have this:
AB is 15 as given.
x = AC
y = BC
x=2y according to description and simple substitution.
ALSO, x+y=15.
Again simple substitution will give you a simple one-variable equation:
x+y=15
2y+y=15
3y=15
Divide both sides by 3,
y=5. This means x=1*5=10.
ANSWER----------------------
AC = 10 and BC =5
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