SOLUTION: The price a flower shop charges for roses is inversely proportional to the number of days before Valentine's Day that the order is placed. A dozen roses ordered ten days before val
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Question 77341: The price a flower shop charges for roses is inversely proportional to the number of days before Valentine's Day that the order is placed. A dozen roses ordered ten days before valentine's Day costs $12.00 while the same order placed five days before Valentine's Day costs $24.00. What is the cost of a dozen roses ordered one day before Valentine's day? Found 2 solutions by stanbon, ankor@dixie-net.com:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The price a flower shop charges for roses is inversely proportional to the number of days before Valentine's Day that the order is placed.
P = k/d
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A dozen roses ordered ten days before valentine's Day costs $12.00 while the same order placed five days before Valentine's Day costs $24.00.
12 = k/10
k=120
Therefore, Formula: P=120/d
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What is the cost of a dozen roses ordered one day before Valentine's day?
p=120/1 = $120
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Cheers,
Stan H.
You can put this solution on YOUR website! The price a flower shop charges for roses is inversely proportional to the number of days before Valentine's Day that the order is placed. A dozen roses ordered ten days before valentine's Day costs $12.00 while the same order placed five days before Valentine's Day costs $24.00. What is the cost of a dozen roses ordered one day before Valentine's day?
:
One way is to write a linear equation by finding the slope and using the
point/slope equation:
:
Let x = number of days from v. day
Then y = cost of the roses on that day
:
x1 = 10, y1 = 12; x2 = 5, y2 = 24
:
Find the slope; m = (y2-y1)/(x2-x1):
:
m = = = -12/5 = -2.4
:
Use the point/slope equation: y - y1 = m(x - x1)
:
y - 12 = -2.4(x - 10)
y - 12 = -2.4x - (-24)
y - 12 = -2.4x + 24
y = -2.4x + 24 + 12
y = -2.4x + 36
;
Substitute 1 for x:
y = 2.4(1) +36
y = $33.60 1 day before v. day