SOLUTION: Find the equation of the tangent to the circle with centre: (3,-1) at (-1,1)

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Question 770886: Find the equation of the tangent to the circle with centre: (3,-1) at (-1,1)
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
the slope between (-1,1) and (3,-1) is

m=(-1-1)/(3-(-1))=-1/2
which must be perpendicular to our line's slope. Therefore using
%0D%0Ay-y%5B0%5D+=+m%28x-x%5B0%5D%29%0D%0A
we have
%0D%0Ay-1+=2%28x%2B1%29%0D%0A