SOLUTION: Suppose the diameter of a circle is 90 inches long and a chord is 54 inches long. Find the distance between the chord and the center of the circle.
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-> SOLUTION: Suppose the diameter of a circle is 90 inches long and a chord is 54 inches long. Find the distance between the chord and the center of the circle.
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Question 769706: Suppose the diameter of a circle is 90 inches long and a chord is 54 inches long. Find the distance between the chord and the center of the circle. Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Consider a right angled triangle.
The radius (half the diameter = 45ins)
is the hypotenuse.
And half of the chord is the base of
the right angled triangle = 27ins.
The distance from the centre is
represented by the vertical side
of the triangle
Vertical side^2 + Base side^2 = Radius^2
Vertical side^2 = Radius^2 - Base side^2
Vertical side^2 = 45^2 - 27^2
Vertical side^2 = 1296
Vertical side =
Distance chord and centre = 36ins
Hope this helps.
:-)
