SOLUTION: Please someone help me solve this problem: *Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side

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Question 769002: Please someone help me solve this problem:
*Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side. Find its length and width.
Thank You!
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Since the rectangles are similar, the relationships between the length and width are the same, so we can write it
let x be the shorter side
%282x%2B8%29%2Fx+=+12%2F5........cross multiply
5%282x%2B8%29+=+12x
10x+%2B+40+=+12x
40+=+12x+-+10x
40+=+2x
x+=+40%2F2
x+=+20cm...... the shorter side
then the longer side is:
2%2820%29%2B8+=+48cm
so, the 2nd rectangle is 48 by 20