SOLUTION: What is the perimeter of a rectangle with a length of 2 yd and 8 ft and a width of 6 ft?
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Question 758339
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What is the perimeter of a rectangle with a length of 2 yd and 8 ft and a width of 6 ft?
Answer by
Cromlix(4381)
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Perimeter = 2 x length + 2 x width
= 2 x 14ft + 2 x 6ft
= 28ft + 12ft
= 40ft.
Hope this helps.
:-)