SOLUTION: Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2).
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-> SOLUTION: Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2).
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Question 750706: Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2). Answer by tommyt3rd(5050) (Show Source):
You can put this solution on YOUR website! since our two lines are parallel, the circle's diameter must be 6-1=5 (and so r=5/2)
This means that the x-coordinate of the center must 1+5/2=7/2
Next we can write:
after solving we determine that k=0.
therefore...
