SOLUTION: what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?

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Question 748722: what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?
Found 2 solutions by Cromlix, stanbon:
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Formula for a circle:
(x - a)^2 + (y - b)^2 = r^2
(x-3)^2+(y+7)^2=36
Therefore the coordinates of the circle
is (3, -7)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what are the coordinates of the center of the circle whose equation is (x-3)^2+(y+7)^2=36?
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Ans: (3,-7)
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Cheers,
Stan H.
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