SOLUTION: Find the equation of the line satisfying the given conditions : Perpendicular to the graph of y + 6 = -1/3x and passes through the point at (-4,-5)

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Question 73464: Find the equation of the line satisfying the given conditions : Perpendicular to the graph of y + 6 = -1/3x and passes through the point at (-4,-5)
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
Y+6=-X/3
Y=-X/3-6 THIS LINE HAS A SLOPE OF -1/3 SO A PERPENDICULAR LINE HAS A SLOPE OF 3.
NOW REEPLACE THE X&Y VALUES & THE SLOPE (m) IN THE LINE EQUATION (Y=mX+b) & SOLVE FOR THE Y INTERCEPT(b)
-5=-4*3+b
-5=-12+b
b=-5+12
b=7 THUS THE LINE EQUATION IS:
Y=3X+7
FOLLOWING IS THE GRAPH OF THESE TWO LINES:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-x%2F3+-6%2C+y+=+3x+%2B7%29+ (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -x/3 -6 and y = 3x +7).