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| Question 709805:  Write an equation of the line that is the perpendicular bisector of the line segment having endpoints (3,-1) and (3,5).
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Write an equation of the line that is the perpendicular bisector of the line segment having endpoints (3,-1) and (3,5). ------
 slope of line thru given points: (5--1)/(3-3) = undefined
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 Therefore slope of perpendicular bisector: m = 0
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 Midpoint of given segment:
 x = (3+3)/2 = 3
 y = (-1+5)/2 = 2
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 Midpoint is (3,2)
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 If slope = 0, the line is a horizontal line thru (3,2)
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 Equation of perp/bisector: y = 2
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 Cheers,
 Stan H.
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